Generar rango numérico en Bash
Usando seq
Syntax:
seq LAST
seq FIRST LAST
seq FIRST INCREMENT LAST
seq FIRST LAST
seq FIRST INCREMENT LAST
Code:
$ seq 5 10
$ seq 0 2 10
$ seq 5 -1 1
$ seq 0 2 10
$ seq 5 -1 1
Script:
#!/bin/bash
for i in `seq 5`
do
echo "Welcome $i times"
done
for i in `seq 5`
do
echo "Welcome $i times"
done
Usando for
#!/bin/bash
for ((a=1; a<=5; a++))
do
echo "Welcome $i times"
done
for ((a=1; a<=5; a++))
do
echo "Welcome $i times"
done
